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프로그래밍/Spring

[Spring] 오라클 연결 설정 및 context를 불러오는 과정

by Youngs_ 2021. 12. 3.

처음 실행할때 프로젝트의 web.xml실행

web.xml

<context-param>
		<param-name>contextConfigLocation</param-name>
		<param-value>classpath*:*-context.xml</param-value>
	</context-param>
	
	

	<servlet>
		<servlet-name>dispatcherServlet</servlet-name>
		<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
		<init-param>
			<param-name>contextConfigLocation</param-name>
			<param-value>classpath*:/spring/servlet-context.xml</param-value>
		</init-param>
		<load-on-startup>1</load-on-startup>
	</servlet>

web.xml에서 servlet-context와 root-context를 불러옴

 

servlet-context

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
    xmlns:security="http://www.springframework.org/schema/security"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:beans="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context
        http://www.springframework.org/schema/context/spring-context.xsd
        http://www.springframework.org/schema/mvc
        http://www.springframework.org/schema/mvc/spring-mvc.xsd
        http://www.springframework.org/schema/security
       http://www.springframework.org/schema/security/spring-security.xsd
       ">
	<annotation-driven />
	
    <resources mapping="/resources/**" location="/resources/" /> 
	 
	<beans:bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> 
		<beans:property name="prefix" value="/WEB-INF/jsp/"/>
		<beans:property name="suffix" value=".jsp"/>
	</beans:bean>
	
	<context:component-scan base-package="main">
		<context:include-filter type="annotation" expression="org.springframework.stereotype.Controller"/>
	</context:component-scan>
	 
    
</beans:beans>

root-context

<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
    <property name="driverClassName" value="net.sf.log4jdbc.sql.jdbcapi.DriverSpy"></property>
    <property name="url" value="jdbc:log4jdbc:oracle:thin:@localhost:1521:xe"></property>
    <property name="username" value="아이디"></property>
    <property name="password" value="비밀번호"></property>
</bean>
 
 <!-- mybatis -->
    <bean id="sqlSession" class="org.mybatis.spring.SqlSessionTemplate" destroy-method="clearCache">
		<constructor-arg name="sqlSessionFactory" ref="sqlSessionFactory"></constructor-arg>
	</bean>
	
	
<bean id="sqlSessionFactory" class="org.mybatis.spring.SqlSessionFactoryBean">
	<property name="dataSource" ref="dataSource" />
	<property name="configLocation" value="classpath:/mybatis-config.xml"></property>
	<property name="mapperLocations">
		<array>
			<value> classpath:/main/java/com/mobile/sqlmap/**/*Mapper.xml </value>
			<value> classpath:/sqlmap/**/*Mapper.xml </value>
		</array>
	</property>
</bean>

 

 


No qualifying bean of type 'org.apache.ibatis.session.SqlSession' available 에러가 나서 한참을 고생했는데 알고보니 프로젝트의 web.xml에 경로가 잘못 입력된것이었다. 어쩐지 bean을 추가를 해도 bean을 찾을수없다고 나오더라..ㅠㅠ

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